Tip

Find duplicate indexes

This script returns duplicate indexes on the current database. It uses two user-defined functions that are compatible with SQL Server 2000 (I used SP3). It won't work in SQL Server 7.0 because of the user-defined functions and a memory table.

 /*
Find Duplicate Indexes  
This script returns the duplicate indexes on any database. 
Created by G.R. Preethiviraj Kulasingham B.Sc., MCP   
Written on  : February  20, 2003    
Modified on : May 22, 2003    
*/

IF EXISTS(Select id from sysobjects Where id = object_id('dbo.GetColID'))
   DROP FUNCTION dbo.getColID

GO

Create Function dbo.getColID (@Tableid int, @indid int) 
Returns Varchar(2000) 
As
BEGIN
     Declare @SQL varchar(2000)
     Set @SQL =''
     Select @SQL= @SQL +','+  convert(varchar(5),
((indexkey_property(id, indid, keyno, 'isdescending')*2)-1)* colid)  
from sysindexkeys
     Where id =@Tableid and indid=@Indid 
     Order by id, indid, Keyno 
     IF LEN(@SQL)>1
          Select @SQL = SUbString(@SQL, 2, LEN(@SQL)-1)
     Return @SQL
END
GO


IF EXISTS(Select id from sysobjects 
Where id = object_id('dbo.GetColList'))
   DROP FUNCTION dbo.getColList

GO

Create Function dbo.getColList (@Tableid int, @indid int) 
Returns Varchar(8000) 
As
BEGIN
     Declare @SQL varchar(8000)
     Set @SQL =''
     Select @SQL= @SQL +','+ 
INDEX_Col(Object_name(@TableID), @indid, keyno)  
from sysindexkeys 
     Where id =@Tableid and indid=@Indid 
     Order by id, indid, Keyno 
     IF

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LEN(@SQL)>1 Select @SQL = SUbString(@SQL, 2, LEN(@SQL)-1) Return @SQL END GO Declare @TempTable Table ( ID int , Indid int, ColID Varchar(2000), ColNames Varchar(8000) ) Insert into @TempTable Select Id, indid, dbo.GetColid(id, indid), dbo.GetColList(id, indid) from Sysindexes order by id Delete @TempTable Where ColNames='' Select O.Name 'Table', I.Name 'Index', B.ColNames 'Column(s)' From SysObjects O, Sysindexes I, @TempTable B, (Select id, ColID, Count(Indid) as inst from @TempTable Group By id, ColID, ColNames HAving Count(indid)>1) A Where A.id = B.id and A.ColID= B.colID and B.id =i.id and B.indid = i.indid and i.id = o.id

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This was first published in February 2005

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