Return only the date from a SQL smalldatetime field

Get code to return only the date part of the SQL datetime field in this ITKnowledge Exchange discussion.

The following question and answer appeared in our ITKnowledge Exchange discussion forums: Return only the date part of a SQL smalldatetime field

Question

Member "bjack8468" writes: Does anyone know how to return only the date part of the SQL datetime field? Or how to convert an integer field to a date field? For example, I need to convert integer 20060223 to a date field. The sysjobhistory table stores the run_date as an integer and I need to query sysjobhistory for run_date = getdate(), but because the type is different, they cannot be compared. I'd really appreciate any feedback you may have.

Answers

Member "CharlesJC" writes: There may be a more efficient way to do this, like making a function that converts the date to an integer, but you could compare run_date to

select cast(
cast(year(getdate()) as varchar) + 
case len(cast(month(getdate())as varchar))
when 1 then
'0' + cast(month(getdate())as varchar)
else
cast(month(getdate())as varchar)
end + 
case len(cast(day(getdate())as varchar))
when 1 then
'0' + cast(day(getdate())as varchar)
else
cast(day(getdate())as varchar)
end as int)

Member "jaylou" writes: Try this:

select * from msdb..sysjobhistory where run_date = CONVERT(CHAR(8),getdate(), 112)

This will get you want you asked for.

Below are more samples to change around dates. (Notice I placed the date in ticks. You get an arithmatic overflow if you leave the int as an int.)

declare @date datetime
select @date = '20060223'
select @date 
-- this will give you only the date part of @date
select convert(varchar(12),getdate(),101)

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This was first published in March 2006

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